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0=5x^2-22x+25
We move all terms to the left:
0-(5x^2-22x+25)=0
We add all the numbers together, and all the variables
-(5x^2-22x+25)=0
We get rid of parentheses
-5x^2+22x-25=0
a = -5; b = 22; c = -25;
Δ = b2-4ac
Δ = 222-4·(-5)·(-25)
Δ = -16
Delta is less than zero, so there is no solution for the equation
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